66 lines
1.9 KiB
Diff
66 lines
1.9 KiB
Diff
From f0bd54cb83ba430ef81153c7a6da2a52daca5266 Mon Sep 17 00:00:00 2001
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From: Michel Thebeau <michel.thebeau@windriver.com>
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Date: Mon, 25 Jul 2016 11:23:18 -0400
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Subject: [PATCH] run-parts: add option to remove printing of motd script name
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The awk statement seems to be a round-about way of printing the name of
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the motd script (/etc/motd.d/*). The pipe seems to allow awk to print
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without user input; while the end of input causes awk to exit. Any
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input to awk is echoed to terminal before the motd script name is
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printed.
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The script name that is printed is appended to /etc/motd. This is
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undesirable. Add an option to skip the awk program.
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Signed-off-by: Michel Thebeau <michel.thebeau@windriver.com>
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---
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run-parts | 25 +++++++++++++++++++------
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1 file changed, 19 insertions(+), 6 deletions(-)
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diff --git a/run-parts b/run-parts
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index 7e148f8..b444f4e 100755
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--- a/run-parts
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+++ b/run-parts
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@@ -4,6 +4,14 @@
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# keep going when something fails
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set +e
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+# First parameter to remove printing of the names of executed scripts.
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+# The default is unmodified behaviour, print the name of scripts.
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+with_progname="y"
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+if [ "$1" == "--without-progname" ]; then
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+ with_progname=""
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+ shift
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+fi
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+
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if [ $# -lt 1 ]; then
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echo "Usage: run-parts [--list | --test] <dir>"
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exit 1
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@@ -87,12 +95,17 @@ for i in $(LC_ALL=C; echo ${1%/}/*[^~,]) ; do
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# run executable files
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logger -p cron.notice -t "run-parts($1)[$$]" "starting $(basename $i)"
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- $i 2>&1 | awk -v "progname=$i" \
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- 'progname {
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- print progname ":\n"
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- progname="";
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- }
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- { print; }'
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+ if [ -n "$with_progname" ]; then
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+ $i 2>&1 | awk -v "progname=$i" \
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+ 'progname {
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+ print progname ":\n"
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+ progname="";
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+ }
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+ { print; }'
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+ else
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+ $i 2>&1
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+ fi
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+
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logger -i -p cron.notice -t "run-parts($1)" "finished $(basename $i)"
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fi
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fi
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--
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1.8.3.1
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